The figure below shows a black and white table mat that Mrs Lee bought. The diameter of each circle is k cm. (take pi = 22/7) a) find the perimeter of the table mat in terms of k. b) Mrs Lee placed the mat on a table which is 0.85m long and 0.5m wide.[…]
Notice that area of triangle BIE = 1/2 * width (IE) * height (22cm) also, area of triangle CIJ = 1/2 * width (IJ) * height (22cm) the two triangles overlap on the quadrilateral FGHI. so sum of triangles – FGHI = unshaded area. we don’t know IE and IJ but we know that IE[…]
Maths tip: Here’s a challenging area question.
Maths tip: Here’s another challenging maths question. Solving by algebra is hard too! Let’s try other methods of solving it 🙂
Maths tip: Here’s an interesting area question. Take a look!
Maths tip: Another area question that seems to be quite popular. 2 solution methods are presented 🙂
Maths tip: Area problems can be challenging. One way to tackle these is to familiarise yourself with some of the problems and get an idea of how to solve them. Here’s one example. Try it!
Maths tip: The figure below consists of two semi circles with diameter 12cm and a sector of a circle with radius 12cm. Find the area of the shaded part, rounding your answer to the nearest whole number. Answer will come in the comment box.
Good question from one of our readers. Question: The shaded region is bounded by an equilateral triangle and 2 quarter arcs. Find the area of the shaded part, rounding off your answer to the nearest whole number. Answer’s way below